Best practices regarding equals: to overload or not to overload?
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Published on 2010-05-26T06:23:35Z
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2010/05/26
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Consider the following snippet:
import java.util.*;
public class EqualsOverload {
public static void main(String[] args) {
class Thing {
final int x;
Thing(int x) { this.x = x; }
public int hashCode() { return x; }
public boolean equals(Thing other) { return this.x == other.x; }
}
List<Thing> myThings = Arrays.asList(new Thing(42));
System.out.println(myThings.contains(new Thing(42))); // prints "false"
}
}
Note that contains
returns false
!!! We seems to have lost our things!!
The bug, of course, is the fact that we've accidentally overloaded, instead of overridden, Object.equals(Object)
. If we had written class Thing
as follows instead, then contains
returns true
as expected.
class Thing {
final int x;
Thing(int x) { this.x = x; }
public int hashCode() { return x; }
@Override public boolean equals(Object o) {
return (o instanceof Thing) && (this.x == ((Thing) o).x);
}
}
Effective Java 2nd Edition, Item 36: Consistently use the Override annotation, uses essentially the same argument to recommend that @Override
should be used consistently. This advice is good, of course, for if we had tried to declare @Override equals(Thing other)
in the first snippet, our friendly little compiler would immediately point out our silly little mistake, since it's an overload, not an override.
What the book doesn't specifically cover, however, is whether overloading equals
is a good idea to begin with. Essentially, there are 3 situations:
- Overload only, no override -- ALMOST CERTAINLY WRONG!
- This is essentially the first snippet above
- Override only (no overload) -- one way to fix
- This is essentially the second snippet above
- Overload and override combo -- another way to fix
The 3rd situation is illustrated by the following snippet:
class Thing {
final int x;
Thing(int x) { this.x = x; }
public int hashCode() { return x; }
public boolean equals(Thing other) { return this.x == other.x; }
@Override public boolean equals(Object o) {
return (o instanceof Thing) && (this.equals((Thing) o));
}
}
Here, even though we now have 2 equals
method, there is still one equality logic, and it's located in the overload. The @Override
simply delegates to the overload.
So the questions are:
- What are the pros and cons of "override only" vs "overload & override combo"?
- Is there a justification for overloading
equals
, or is this almost certainly a bad practice?
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