python processs complete list files matched
Posted
by thomytheyon
on Stack Overflow
See other posts from Stack Overflow
or by thomytheyon
Published on 2010-05-26T06:38:53Z
Indexed on
2010/05/26
6:41 UTC
Read the original article
Hit count: 215
Hi All,
I'm trying to get a simple code working, unfortunatly im a python beginner.
My script should return a list of files that doesn't match a pattern, more information here : http://stackoverflow.com/questions/2910106/python-grep-reverse-matching/2910288#2910288
My code is running but doesn't process the complete list of files found as it should :
import sys,os
filefilter = ['.xml','java','.jsp','lass']
path= "/home/patate/code/project"
s = "helloworld"
for path, subdirs, files in os.walk(path):
for name in files:
if name[-4:] in filefilter :
f = str(os.path.join(path, name))
with open(f) as fp:
if s in fp.read():
print "%s has the string" % f
else:
print "%s doesn't have the string" % f
This code return :
/home/patate/code/project/blabla/blabla/build.xml doesn't have the string
None
If i change f = str(os.path.join(path, name)) for print str(os.path.join(path, name)) I can see the whole list being printed.
How can i process the whole list as i which to ? :(
Thanks again.
© Stack Overflow or respective owner