Is it possible a lambda function to have variable number of arguments? For example, I want to write a metaclass, which creates a method for every method of some other class and this newly created method returns the opposite value of the original method and has the same number of arguments. And I want to do this with lambda function. How to pass the arguments? Is it possible?

class Negate(type):
    def __new__(mcs, name, bases, _dict):
        extended_dict = _dict.copy()
        for (k, v) in _dict.items():
            if hasattr(v, '__call__'):
                extended_dict["not_" + k] = lambda s, *args, **kw:  not v(s, *args, **kw)
        return type.__new__(mcs, name, bases, extended_dict)

class P(metaclass=Negate):
    def __init__(self, a):
        self.a = a

    def yes(self):
        return True

    def maybe(self, you_can_chose):
        return you_can_chose

But the result is totally wrong:

>>>p = P(0)
>>>p.yes()
True
>>>p.not_yes()     # should be False
Traceback (most recent call last):
  File "<pyshell#150>", line 1, in <module>
    p.not_yes()
  File "C:\Users\Nona\Desktop\p10.py", line 51, in <lambda>
    extended_dict["not_" + k] = lambda s, *args, **kw:  not v(s, *args, **kw)
TypeError: __init__() takes exactly 2 positional arguments (1 given)
>>>p.maybe(True)
True
>>>p.not_maybe(True)     #should be False
True