Setting attributes of a class during construction from **kwargs
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by Carson Myers
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Published on 2010-05-28T04:07:22Z
Indexed on
2010/05/28
4:11 UTC
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Python noob here,
Currently I'm working with SQLAlchemy, and I have this:
from __init__ import Base
from sqlalchemy.schema import Column, ForeignKey
from sqlalchemy.types import Integer, String
from sqlalchemy.orm import relationship
class User(Base):
__tablename__ = "users"
id = Column(Integer, primary_key=True)
username = Column(String, unique=True)
email = Column(String)
password = Column(String)
salt = Column(String)
openids = relationship("OpenID", backref="users")
User.__table__.create(checkfirst=True)
#snip definition of OpenID class
def create(**kwargs):
user = User()
if "username" in kwargs.keys():
user.username = kwargs['username']
if "email" in kwargs.keys():
user.username = kwargs['email']
if "password" in kwargs.keys():
user.password = kwargs['password']
return user
This is in /db/users.py
, so it would be used like:
from db import users
new_user = users.create(username="Carson", password="1234")
new_user.email = "[email protected]"
users.add(new_user) #this function obviously not defined yet
but the code in create()
is a little stupid, and I'm wondering if there's a better way to do it that doesn't require an if ladder, and that will fail if any keys are added that aren't in the User object already. Like:
for attribute in kwargs.keys():
if attribute in User:
user.__attribute__[attribute] = kwargs[attribute]
else:
raise Exception("blah")
that way I could put this in its own function (unless one hopefully already exists?) So I wouldn't have to do the if ladder again and again, and so I could change the table structure without modifying this code.
Any suggestions?
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