Why does Python's 'for ... in' work differently on a list of values vs. a list of dictionaries?

Posted by Code Duck on Stack Overflow See other posts from Stack Overflow or by Code Duck
Published on 2010-05-28T04:03:52Z Indexed on 2010/05/28 4:11 UTC
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I'm wondering about some details of how for ... in works in Python.

My understanding is for var in iterable on each iteration creates a variable, var, bound to the current value of iterable. So, if you do for c in cows; c = cows[whatever], but changing c within the loop does not affect the original value. However, it seems to work differently if you're assigning a value to a dictionary key.

cows=[0,1,2,3,4,5]
for c in cows:
  c+=2

#cows is now the same - [0,1,2,3,4,5]

cows=[{'cow':0},{'cow':1},{'cow':2},{'cow':3},{'cow':4},{'cow':5}]
for c in cows:
  c['cow']+=2

# cows is now [{'cow': 2}, {'cow': 3}, {'cow': 4}, {'cow': 5}, {'cow': 6}, {'cow': 7}
#so, it's changed the original, unlike the previous example

I see one can use enumerate to make the first example work, too, but that's a different story, I guess.

cows=[0,1,2,3,4,5]
for i,c in enumerate(cows):
  cows[i]+=1

# cows is now [1, 2, 3, 4, 5, 6]

Why does it affect the original list values in the second example but not the first?

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