Can you get a Func<T> (or similar) from a MethodInfo object?

Posted by Dan Tao on Stack Overflow See other posts from Stack Overflow or by Dan Tao
Published on 2010-05-29T00:06:23Z Indexed on 2010/05/29 0:12 UTC
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I realize that, generally speaking, there are performance implications of using reflection. (I myself am not a fan of reflection at all, actually; this is a purely academic question.)

Suppose there exists some class that looks like this:

public class MyClass {
    public string GetName() {
        return "My Name";
    }
}

Bear with me here. I know that if I have an instance of MyClass called x, I can call x.GetName(). Furthermore, I could set a Func<string> variable to x.GetName.

Now here's my question. Let's say I don't know the above class is called MyClass; I've got some object, x, but I have no idea what it is. I could check to see if that object has a GetName method by doing this:

MethodInfo getName = x.GetType().GetMethod("GetName");

Suppose getName is not null. Then couldn't I furthermore check if getName.ReturnType == typeof(string) and getName.GetParameters().Length == 0, and at this point, wouldn't I be quite certain that the method represented by my getName object could definitely be cast to a Func<string>, somehow?

I realize there's a MethodInfo.Invoke, and I also realize I could always create a Func<string> like:

Func<string> getNameFunc = () => getName.Invoke(x, null);

I guess what I'm asking is if there's any way to go from a MethodInfo object to the actual method it represents, incurring the performance cost of reflection in the process, but after that point being able to call the method directly (via, e.g., a Func<string> or something similar) without a performance penalty.

What I'm envisioning might look something like this:

// obviously this would throw an exception if GetActualInstanceMethod returned
// something that couldn't be cast to a Func<string>
Func<string> getNameFunc = (Func<string>)getName.GetActualInstanceMethod(x);

(I realize that doesn't exist; I'm wondering if there's anything like it.)

If what I'm asking doesn't make sense, or if I'm being unclear, I'll be happy to attempt to clarify.

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