Django QuerySet API: How do I join iexact and icontains?
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Published on 2010-01-20T17:34:54Z
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2010/05/30
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django
|django-queryset
Hello,
I have this join:
lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name)
If you try Last Name: Abbas and First Name: Amr it tells you that amr abbas has 1 schoolmates.
But if you try First name only it says that there are no lawyers in the database called amr (obviously there is).
If I change (last__iexact=last_name)
to (last__icontains=last_name)
then leaving Last Name blank works fine and amr is found.
But with last__icontains=last_name
if you search for "collin" you also get "collins" and "collingwood" which is not what I want.
Do you know how I can use iexact
and also have it ignored if it is blank?
Thanks
This is the view function:
def search_form(request):
if request.method == 'POST':
search_form = SearchForm(request.POST)
if search_form.is_valid():
last_name = search_form.cleaned_data['last_name']
first_name = search_form.cleaned_data['first_name']
lawyers = Lawyer.objects.filter(last__iexact=last_name).filter(first__icontains=first_name)
if len(lawyers)==0:
form = SearchForm()
return render_to_response('not_in_database.html', {'last': last_name, 'first': first_name, 'form': form})
if len(lawyers)>1:
form = SearchForm(initial={'last_name': last_name})
return render_to_response('more_than_1_match.html', {'lawyers': lawyers, 'last': last_name, 'first': first_name, 'form': form})
q_school = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('school', flat=True)
q_year = Lawyer.objects.filter(last__icontains=last_name).filter(first__icontains=first_name).values_list('year_graduated', flat=True)
lawyers1 = Lawyer.objects.filter(school__iexact=q_school[0]).filter(year_graduated__icontains=q_year[0]).exclude(last__icontains=last_name)
form = SearchForm()
return render_to_response('search_results.html', {'lawyers': lawyers1, 'last': last_name, 'first': first_name, 'form': form})
else:
form = SearchForm()
return render_to_response('search_form.html', {'form': form, })
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