sorting a doubly linked list with merge sort.

Posted by user329820 on Stack Overflow See other posts from Stack Overflow or by user329820
Published on 2010-05-30T11:56:41Z Indexed on 2010/05/30 12:02 UTC
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Hi I have found this code in the internet and it was for arrays ,I want to change it for doubly linked list(instead of index we should use pointer) would you please help me that how can i change merge method(I have changed sort method by myself) also this is not my home work ,I love working with linked list!!

public class MergeSort {

private DoublyLinkedList LocalDoublyLinkedList;

public MergeSort(DoublyLinkedList list) {
    LocalDoublyLinkedList = list;

}

public void sort() {

    if (LocalDoublyLinkedList.size() <= 1) {
        return;
    }
    DoublyLinkedList listOne = new DoublyLinkedList();
    DoublyLinkedList listTwo = new DoublyLinkedList();
    for (int x = 0; x < (LocalDoublyLinkedList.size() / 2); x++) {
        listOne.add(x, LocalDoublyLinkedList.getValue(x));
}
for (int x = (LocalDoublyLinkedList.size() / 2) + 1; x < LocalDoublyLinkedList.size`(); x++) {`
    listTwo.add(x, LocalDoublyLinkedList.getValue(x));
}
//Split the DoublyLinkedList again
    MergeSort sort1 = new MergeSort(listOne);
    MergeSort sort2 = new MergeSort(listTwo);
    sort1.sort();
    sort2.sort();

    merge(listOne, listTwo);
}

private void merge(DoublyLinkedList a, DoublyLinkedList b) {
    int x = 0;
    int y = 0;
    int z = 0;
    while (x < first.length && y < second.length) {
        if (first[x] < second[y]) {
            a[z] = first[x];
            x++;
        } else {
            a[z] = second[y];
            y++;
        }
        z++;
    }
//copy remaining elements to the tail of a[];
    for (int i = x; i < first.length; i++) {
        a[z] = first[i];
        z++;
    }
    for (int i = y; i < second.length; i++) {
        a[z] = second[i];
        z++;
    }
}
}

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