C#: why Base class is allowed to implement an interface contract without inheriting from it?

Posted by etarassov on Stack Overflow See other posts from Stack Overflow or by etarassov
Published on 2010-05-31T10:00:21Z Indexed on 2010/05/31 10:02 UTC
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I've stumbled upon this "feature" of C# - the base class that implements interface methods does not have to derive from it.

Example:

public interface IContract
{
    void Func();
}

// Note that Base does **not** derive from IContract
public abstract class Base
{
    public void Func()
    {
        Console.WriteLine("Base.Func");
    }
}

// Note that Derived does *not* provide implementation for IContract
public class Derived : Base, IContract
{
}

What happens is that Derived magically picks-up a public method Base.Func and decides that it will implement IContract.Func.

What is the reason behind this magic?

IMHO: this "quasi-implementation" feature is very-unintuitive and make code-inspection much harder. What do you think?

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