Http authentication with apache httpcomponents
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by matdan
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Published on 2010-05-31T17:53:03Z
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2010/05/31
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Hi,
I am trying to develop a java http client with apache httpcomponents 4.0.1. This client calls the page "https://myHost/myPage". This page is protected on the server by a JNDIRealm with a login form authentication, so when I try to get https://myHost/myPage I get a login page. I tried to bypass it unsuccessfully with the following code :
//I set my proxy
HttpHost proxy = new HttpHost("myProxyHost", myProxyPort);
//I add supported schemes
SchemeRegistry supportedSchemes = new SchemeRegistry();
supportedSchemes.register(new Scheme("http", PlainSocketFactory
.getSocketFactory(), 80));
supportedSchemes.register(new Scheme("https", SSLSocketFactory
.getSocketFactory(), 443));
// prepare parameters
HttpParams params = new BasicHttpParams();
HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
HttpProtocolParams.setContentCharset(params, "UTF-8");
HttpProtocolParams.setUseExpectContinue(params, true);
ClientConnectionManager ccm = new ThreadSafeClientConnManager(params,
supportedSchemes);
DefaultHttpClient httpclient = new DefaultHttpClient(ccm, params);
httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY,
proxy);
//I add my authentication information
httpclient.getCredentialsProvider().setCredentials(
new AuthScope("myHost/myPage", 443),
new UsernamePasswordCredentials("username", "password"));
HttpHost host = new HttpHost("myHost", 443, "https");
HttpGet req = new HttpGet("/myPage");
//show the page
ResponseHandler<String> responseHandler = new BasicResponseHandler();
String rsp = httpClient.execute(host, req, responseHandler);
System.out.println(rsp);
When I run this code, I always get the login page, not myPage. How can I apply my credential parameters to avoid this login form?
Any help would be fantastic
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