Doctrine: how to create a query using "LIKE REPLACE" ?
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Published on 2010-06-01T13:29:32Z
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2010/06/01
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Hi,
this SQL clause is working OK:
SELECT * FROM `sf_guard_user` WHERE nombre_apellidos LIKE REPLACE('Mar Sanz',' ','%')
Now I'm trying to write this query for Doctrine. I have tried this:
$query->andWhere(sprintf('%s.%s LIKE REPLACE (?," ","%")',
$query->getRootAlias(), $fieldName),
'Mar Sanz'));
but I get this error:
Warning: sprintf() [function.sprintf]: Too few arguments
Any idea?
Regards
Javi
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