Why is this SQL query throwing Warnings?
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Published on 2010-06-01T12:00:41Z
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2010/06/01
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$resultnx = mysql_query("SELECT * FROM `emails` WHERE `email` = '{$email}'");
$num_rows = mysql_num_rows($resultnx);
gets this warning Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in ....
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