More efficient comparison of numbers
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by Pez Cuckow
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Published on 2010-06-02T16:00:49Z
Indexed on
2010/06/02
16:04 UTC
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I have an array which is part of a small JS game I am working on I need to check (as often as reasonable) that each of the elements in the array haven't left the "stage" or "playground", so I can remove them and save the script load
I have coded the below and was wondering if anyone knew a faster/more efficient way to calculate this. This is run every 50ms (it deals with the movement).
Where bots[i][1]
is movement in X and bots[i][2]
is movement in Y (mutually exclusive).
for (var i in bots) {
var left = parseInt($("#" + i).css("left"));
var top = parseInt($("#" + i).css("top"));
var nextleft = left + bots[i][1];
var nexttop = top + bots[i][2];
if(bots[i][1]>0&&nextleft>=PLAYGROUND_WIDTH) { remove_bot(i); }
else if(bots[i][1]<0&&nextleft<=-GRID_SIZE) { remove_bot(i); }
else if(bots[i][2]>0&&nexttop>=PLAYGROUND_HEIGHT) { remove_bot(i); }
else if(bots[i][2]<0&&nexttop<=-GRID_SIZE) { remove_bot(i); }
else {
//alert(nextleft + ":" + nexttop);
$("#" + i).css("left", ""+(nextleft)+"px");
$("#" + i).css("top", ""+(nexttop)+"px");
}
}
On a similar note the remove_bot(i); function is as below, is this correct (I can't splice as it changes all the ID's of the elements in the array.
function remove_bot(i) {
$("#" + i).remove();
bots[i] = false;
}
Many thanks for any advice given!
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