pagination using php with mysql data
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by pradeep
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Published on 2010-06-02T20:02:53Z
Indexed on
2010/06/02
20:04 UTC
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php
i am trying to create a pagination in which there are 5 items at a time depending on the number of items in DB. i wrote this code . but i dono how to go further .its buggy..any better pagination or alteration for this
<?php
$myresult .= "<div class='pagination' >";
if ($pagenum == 1)
{
}
else
{
$pagenum = 1;
$myresult .= "<a href='javascript:newPage(\"".$pagenum."\")'> first </a>";
$myresult .= " ";
$previous = $pagenum-1;
$myresult .= "<a href='javascript:newPage(\"".$previous."\")'> Prev </a>";
if ($pagenum == $last)
{
$previous3 = $pagenum-4;
$myresult .= "<a href='javascript:newPage(\"".$previous3."\")'> $previous3 </a>";
$previous2 = $pagenum-3;
$myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> $previous2 </a>";
}
if ($pagenum > 2)
{
$previous1 = $pagenum-2;
$myresult .= "<a href='javascript:newPage(\"".$previous1."\")'> $previous1 </a>";
}
if ($pagenum > 1)
{
$previous2 = $pagenum-1;
$myresult .= "<a href='javascript:newPage(\"".$previous2."\")'> $previous2 </a>";
$myresult .= " ";
}
}
$myresult .= "<span class=\"disabled\"> $pagenum </span>";
if ($pagenum == $last)
{
}
else {
if($pagenum < $last - 1)
{
$next = $pagenum+1;
$myresult .= "<a href='javascript:newPage(\"".$next."\")'> $next </a>";
}
if($pagenum < $last - 2)
{
$next1 = $pagenum+2;
$myresult .= "<a href='javascript:newPage(\"".$next1."\")'> $next1 </a>";
}
if($pagenum == 1 )
{
$next2 = $pagenum+3;
$myresult .= "<a href='javascript:newPage(\"".$next2."\")'> $next2 </a>";
$next3 = $pagenum+4;
$myresult .= "<a href='javascript:newPage(\"".$next3."\")'> $next3 </a>";
}
if($pagenum == 2 )
{
$next2 = $pagenum+3;
$myresult .= "<a href='javascript:newPage(\"".$next2."\")'> $next2 </a>";
}
$next = $pagenum+1;
$myresult .= "<a href='javascript:newPage(\"".$next."\")'> Next </a>";
$myresult .= "<a href='javascript:newPage(\"".$last."\")'> Last</a>";
}
$myresult .= "</div>";
$myresult .= "</br>";
?>
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