Python - alternative to list.remove(x)?

Posted by Seafoid on Stack Overflow See other posts from Stack Overflow or by Seafoid
Published on 2010-06-02T13:20:27Z Indexed on 2010/06/02 13:34 UTC
Read the original article Hit count: 164

Filed under:
|
|

Hi,

I wish to compare two lists. Generally this is not a problem as I usually use a nested for loop and append the intersection to a new list. In this case, I need to delete the intersection of A and B from A.

 A = [['ab', 'cd', 'ef', '0', '567'], ['ghy5'], ['pop', 'eye']]

 B = [['ab'], ['hi'], ['op'], ['ej']]

My objective is to compare A and B and delete A intersection B from A, i.e., delete A[0][0] in this case.

I tried:

def match():
    for i in A:
        for j in i:
            for k in B:
                for v in k:
                    if j == v:
                        A.remove(j)

list.remove(x) throws a ValueError.

© Stack Overflow or respective owner

Related posts about python

Related posts about comparison