Javascript algorithm to find elements in array that are not in another array
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Published on 2010-06-03T04:14:44Z
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2010/06/03
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I'm looking for a good algorithm to get all the elements in one array that are not elements in another array. So given these arrays:
var x = ["a","b","c","t"];
var ?????????y = [???????"d","a","t","e","g"];
I want to end up with this array:
var z = ["d","e","g"];
I'm using jquery, so I can take advantage of $.each()
and $.inArray()
. Here's the solution I've come up with, but it seems like there should be a better way.
// goal is to get rid of values in y if they exist in x
var x = ["a","b","c","t"];
var y = ["d","a","t","e","g"];
var z = [];
$.each(y, function(idx, value){
if ($.inArray(value,x) == -1) {
z.push(value);
}
});
?alert(z); // should be ["d","e","g"]
Here is the code in action. Any ideas?
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