Visual Studio code generated when choosing to explicitly implement interface
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by fearofawhackplanet
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Published on 2010-06-03T09:22:07Z
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2010/06/03
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Sorry for the vague title, but I'm not sure what this is called.
Say I add IDisposable to my class, Visual Studio can create the method stub for me. But it creates the stub like:
void IDisposable.Dispose()
I don't follow what this syntax is doing. Why do it like this instead of public void Dispose()?
And with the first syntax, I couldn't work out how to call Dispose() from within my class (in my destructor).
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