This function cropit, which I shamelessly stole off the internet, crops a 90x60 area from an existing image.

In this code, when I use the function for more than one item (image) the one will display on top of the other (they come to occupy the same output space).

I think this is because the function has the same (static) name ($dest) for the destination of the image when it's created (imagecopy).

I tried, as you can see to include a second argument to the cropit function which would serve as the "name" of the $dest variable, but it didn't work.

In the interest of full disclosure I have 22 hours of PHP experience (incidentally the same number of hours since the last I slept) and I am not that smart to begin with.

Even if there's something else at work here entirely, seems to me that generally it must be useful to have a way to secure that a variable is always given a unique name.

function cropit($srcimg, $dest) { $im = imagecreatefromjpeg($srcimg); $img_width = imagesx($im); $img_height = imagesy($im);

$width = 90; $height = 60; $tlx = floor($img_width / 2) - floor ($width / 2); $tly = floor($img_height / 2) - floor ($height / 2);

if ($tlx < 0) { $tlx = 0; } if ($tly < 0) { $tly = 0; } if (($img_width - $tlx) < $width) { $width = $img_width - $tlx; } if (($img_height - $tly) < $height) { $height = $img_height - $tly; } $dest = imagecreatetruecolor ($width, $height); imagecopy($dest, $im, 0, 0, $tlx, $tly, $width, $height); imagejpeg($dest); imagedestroy($dest); }

$img = "imagefolder\imageone.jpg"; $img2 = "imagefolder\imagetwo.jpg";

cropit($img, $i1); cropit($img2, $i2); ?>