Why do all procedures have to be defined before the compiler sees them?
Posted
by incrediman
on Stack Overflow
See other posts from Stack Overflow
or by incrediman
Published on 2010-06-04T20:08:47Z
Indexed on
2010/06/08
1:52 UTC
Read the original article
Hit count: 244
For example, take a look at this code (from tspl4):
(define proc1
(lambda (x y)
(proc2 y x)))
If I run this as my program in scheme...
#!r6rs
(import (rnrs))
(define proc1
(lambda (x y)
(proc2 y x)))
I get this error:
expand: unbound identifier in module in: proc2
...This code works fine though:
#!r6rs
(import (rnrs))
(define proc2
+)
(define proc1
(lambda (x y)
(proc2 y x)))
(display (proc1 2 3)) ;output: 5
© Stack Overflow or respective owner