window.open on load page (asp.net) using Method=POST
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by Raul
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Published on 2010-06-08T15:18:08Z
Indexed on
2010/06/08
15:22 UTC
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i need open pop up in asp.net using post Method and window.open to rezise te new windows.
my code:
---- open the pop up ---
function mdpbch(URL) {
child = window.open(URL, "passwd","dependent=1,toolbar=0,location=0,directories=0,status=0,menubar=0,scrollbars=1,resizable=1,width=600,height=475");
child.location.href = URL;
if (child.opener == null) {
child.opener = window;
}
child.opener.name = "opener";
}
-------- URL ---
function PagoEnLinea(Banco)
{
switch(x){
case "BCH":
document.frmEnvia.action = SERV + "/llamacom.asp";
url = SERV + "lamacom.asp
alert(url);
mdpbch(url);
document.frmEnvia.submit();
break;
}
}
-------ASPX--------------------
<body>
<form id="frmEnvia" runat="server" name="formulario" method="post" target="_blank">
<div style="visibility:hidden;">
<asp:TextBox ID="txtXml" runat="server" Visible="true"></asp:TextBox>
</div>
.....
</body>
on page load (code behind) i create a xml string and put it in the textbox txtXml.
i need use post method becose the server validate te method, and window.open becose need customize the pop up
thanks
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