How can i zip files in Java and not include files paths
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by Ignacio
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Published on 2010-06-10T21:15:35Z
Indexed on
2010/06/10
21:42 UTC
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For example, i want to zip a file stored in /Users/me/Desktop/image.jpg
I maded this method:
public static Boolean generateZipFile(ArrayList<String> sourcesFilenames, String destinationDir, String zipFilename){
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// VER SI HAY QUE CREAR EL ROOT PATH
boolean result = (new File(destinationDir)).mkdirs();
String zipFullFilename = destinationDir + "/" + zipFilename ;
System.out.println(result);
// Create the ZIP file
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFullFilename));
// Compress the files
for (String filename: sourcesFilenames) {
FileInputStream in = new FileInputStream(filename);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(filename));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
// Complete the entry
out.closeEntry();
in.close();
} // Complete the ZIP file
out.close();
return true;
} catch (IOException e) {
return false;
}
}
But when i extract the file, the unzipped files have the full path.
I don't want the full path of each file in the zip i only want the filename.
How can i made this?
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