SQL - Rank() on a table
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by Abhi
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Published on 2010-06-10T12:29:14Z
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create table v (mydate,value) as select to_date('20/03/2010 00','dd/mm/yyyy HH24'),98 from dual union all select to_date('20/03/2010 01','dd/mm/yyyy HH24'),124 from dual union all select to_date('20/03/2010 02','dd/mm/yyyy HH24'),140 from dual union all select to_date('20/03/2010 03','dd/mm/yyyy HH24'),138 from dual union all select to_date('20/03/2010 04','dd/mm/yyyy HH24'),416 from dual union all select to_date('20/03/2010 05','dd/mm/yyyy HH24'),196 from dual union all select to_date('20/03/2010 06','dd/mm/yyyy HH24'),246 from dual union all select to_date('20/03/2010 07','dd/mm/yyyy HH24'),176 from dual union all select to_date('20/03/2010 08','dd/mm/yyyy HH24'),124 from dual union all select to_date('20/03/2010 09','dd/mm/yyyy HH24'),128 from dual union all select to_date('20/03/2010 10','dd/mm/yyyy HH24'),32010 from dual union all select to_date('20/03/2010 11','dd/mm/yyyy HH24'),384 from dual union all select to_date('20/03/2010 12','dd/mm/yyyy HH24'),368 from dual union all select to_date('20/03/2010 13','dd/mm/yyyy HH24'),392 from dual union all select to_date('20/03/2010 14','dd/mm/yyyy HH24'),374 from dual union all select to_date('20/03/2010 15','dd/mm/yyyy HH24'),350 from dual union all select to_date('20/03/2010 16','dd/mm/yyyy HH24'),248 from dual union all select to_date('20/03/2010 17','dd/mm/yyyy HH24'),396 from dual union all select to_date('20/03/2010 18','dd/mm/yyyy HH24'),388 from dual union all select to_date('20/03/2010 19','dd/mm/yyyy HH24'),360 from dual union all select to_date('20/03/2010 20','dd/mm/yyyy HH24'),194 from dual union all select to_date('20/03/2010 21','dd/mm/yyyy HH24'),234 from dual union all select to_date('20/03/2010 22','dd/mm/yyyy HH24'),328 from dual union all select to_date('20/03/2010 23','dd/mm/yyyy HH24'),216 from dual
From this table, how to rank() over 'value', partitioning by each hour of the day? and select only the 1st ranked result?
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