Geohashing - recursively find neighbors of neighbors

Posted by itsme on Stack Overflow See other posts from Stack Overflow or by itsme
Published on 2010-06-10T20:45:02Z Indexed on 2010/06/11 7:13 UTC
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I am now looking for an elegant algorithm to recursively find neighbors of neighbors with the geohashing algorithm (http://www.geohash.org).
Basically take a central geohash, and then get the first 'ring' of same-size hashes around it (8 elements), then, in the next step, get the next ring around the first etc. etc. Have you heard of an elegant way to do so?

Brute force could be to take each neighbor and get their neighbors simply ignoring the massive overlap. Neighbors around one central geohash has been solved many times (here e.g. in Ruby: http://github.com/masuidrive/pr_geohash/blob/master/lib/pr_geohash.rb)

Edit for clarification: Current solution, with passing in a center key and a direction, like this (with corresponding lookup-tables):

  def adjacent(geohash, dir)
    base, lastChr = geohash[0..-2], geohash[-1,1]
    type = (geohash.length % 2)==1 ? :odd : :even
    if BORDERS[dir][type].include?(lastChr)
      base = adjacent(base, dir)
    end
    base + BASE32[NEIGHBORS[dir][type].index(lastChr),1]
  end

(extract from Yuichiro MASUI's lib)

I say this approach will get ugly soon, because directions gets ugly once we are in ring two or three. The algorithm would ideally simply take two parameters, the center area and the distance from 0 being the center geohash only (["u0m"] and 1 being the first ring made of 8 geohashes of the same size around it (=> [["u0t", "u0w"], ["u0q", "u0n"], ["u0j", "u0h"], ["u0k", "u0s"]]). two being the second ring with 16 areas around the first ring etc.

Do you see any way to deduce the 'rings' from the bits in an elegant way?

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