PHPUnit: Testing if a protected method was called
Posted
by Luiz Damim
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Published on 2009-11-05T13:36:43Z
Indexed on
2010/06/11
3:42 UTC
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phpunit
I´m trying to test if a protected method is called in a public interface.
<?php
abstract class SomeClassAbstract
{
abstract public foo();
public function doStuff()
{
$this->_protectedMethod();
}
protected function _protectedMethod();
{
// implementation is irrelevant
}
}
<?php
class MyTest extends PHPUnit_Framework_TestCase
{
public function testCalled()
{
$mock = $this->getMockForAbstractClass('SomeClass');
$mock->expects($this->once())
->method('_protectedMethod');
$mock->doStuff();
}
}
I know it is called correctly, but PHPUnit says its never called.
The same happens when I test the other way, when a method is never called:
<?php
abstract class AnotherClassAbstract
{
abstract public foo();
public function doAnotherStuff()
{
$this->_loadCache();
}
protected function _loadCache();
{
// implementation is irrelevant
}
}
<?php
class MyTest extends PHPUnit_Framework_TestCase
{
public function testCalled()
{
$mock = $this->getMockForAbstractClass('AnotherClass');
$mock->expects($this->once())
->method('_loadCache');
$mock->doAnotherStuff();
}
}
The method is called but PHPUnit says that it is not.
What I´m doing wrong?
Edit I wasn´t declaring my methods with double colons, it was just for denoting that it was a public method (interface). Updated to full class/methods declarations.
Edit 2 I should have said that I´m testing some method implementations in an abstract class (edited the code to reflect this). Since I can not instantiate the class, how can I test this?
I´m thinking in creating an SomeClassSimple
extending SomeClassAbstract
and testing this one instead. Is it the right approach?
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