Python 3.1: Windows cant file the file on subprocess.call()

Posted by Srirangan on Stack Overflow See other posts from Stack Overflow or by Srirangan
Published on 2010-06-11T10:27:39Z Indexed on 2010/06/11 10:33 UTC
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Filed under:

python

|

path

|

python-3.x

I am getting the following error:

WindowsError: [Error 2] The system cannot find the file specified

My code is:

subprocess.call(["<<executable file found in PATH>>"])

Windows 7, 64 bit. Python 3.x latest, stable.

Any ideas?

Thanks,

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