In C++0x, methods can be overloaded on whether or not the expression that denotes the object on which the method is called is an lvalue or an rvalue. If I return *this from a method called via an rvalue, do I need to explicitly move from *this or not?

Foo Foo::method() &&
{
    return std::move(*this);   // Is this move required or not?
}

Unfortunately, I can't simply test this on my compiler since g++ does not support this feature yet :(