Passing expression as a parameter in Call by reference
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by darkie15
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Published on 2010-06-12T07:28:43Z
Indexed on
2010/06/12
7:33 UTC
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parameter-passing
All,
When we are passing an expression as a parameter, how does the evaluation occur? Here is a small example. This is just a pseudocode kind of example:
f (x,y)
{
y = y+1;
x = x+y;
}
main()
{
a = 2; b = 2;
f(a+b, a)
print a;
}
When accessing variable x
in f
, does it access the address of the temp variable which contains the result of a+b
or will it access the individual addresses of a
and b
and then evaluate the value of a+b
Please help.
Regards, darkie15
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