Given a Member Access lambda expression, convert it to a specific string representation with full ac
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by Nathan
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Published on 2010-06-15T23:35:15Z
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2010/06/15
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Given an
Expression<Func<T, object>>
(e.g. x => x.Prop1.SubProp), I want to create a string "Prop1.SubProp" for as deep as necessary.
In the case of a single access (e.g. x => x.Prop1), I can easily do this with:
MemberExpression body = (expression.Body.NodeType == ExpressionType.Convert) ? (MemberExpression)((UnaryExpression)expression.Body).Operand : (MemberExpression)expression.Body;
return body.Member.Name;
However, if there is deeper nesting, e.g. x => x.Prop1.SubProp1, this only gets the most deeply nested name, e.g. "SubProp1" instead of "Prop1.SubProp1"
Is there anyway to access the full property path of a lambda expression?
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