How to pass a variable to an awk print parameter...

Posted by Jamie on Stack Overflow See other posts from Stack Overflow or by Jamie
Published on 2010-06-15T18:37:14Z Indexed on 2010/06/15 18:42 UTC
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bash

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awk

I'm trying extract the nth + 1 and nth + 3 columns from a file.

This is what tried, which is a useful pseudo code:

for i in {1..100} ; do awk -F "," " { printf \"%3d, %12.3f, %12.3f\\n\", \$1, \$($i+1), \$($i+3) } " All_Runs.csv > Run-$i.csv

which, obviously doesn't work (but it seemed reasonable to hope).

How can I do this?

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