Bash: trim a parameter from both ends

Posted by Andrey Kazak on Stack Overflow See other posts from Stack Overflow or by Andrey Kazak
Published on 2010-06-16T06:37:09Z Indexed on 2010/06/16 6:42 UTC
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Filed under:

bash

|

parameter

|

expansion

Greetings!

This are well know Bash parameter expansion patterns:

${parameter#word}, ${parameter##word}

and

${parameter%word}, ${parameter%%word}

I need to chop one part from the beginning and anoter part from the trailing of the parameter. Could you advice something for me please?

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