Get URL parameter function that gets value of url part or returns true if it's there but with no val
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Published on 2010-06-16T15:37:40Z
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2010/06/16
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JavaScript
|regex
I'm using the following function to get a URL parameter.
function gup(name, url) {
name = name.replace(/[\[]/, '\\\[').replace(/[\]]/, '\\\]');
var results = new RegExp('[\\?&]'+name+'=?([^&#]*)').exec(url || window.location.href);
return results == null ? null : results[1];
}
It works only if the parameter has a value, for example.
gup('a', 'http://example.com/page.php?a=1&b=2');
will return 1. But if I try
gup('a', 'http://example.com/page.php?a&b=2');
It returns null. I want it to return true because parameter "a" exists in that url, even though it has no value it's still there and gup() should return true. Could I get a bit of help rewriting this? I'm not that good with regex.
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