How can I alter an external variable from inside my AJAX?
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by tmedge
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Published on 2010-06-17T13:55:30Z
Indexed on
2010/06/17
14:43 UTC
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I keep on having these same two problems. I have been trying to use Remy Sharp's wonderful tagSuggest plugin, and it works great. Until I try to use an AJAX call to get tags from my database.
My setGlobalTags()
works great, with my defined myTagList at the top of the function. What I want to do is set myTagList equal to the result from my AJAX. My problem is that I can neither call setGlobalTags()
from inside my success or error functions, nor actually alter the original myTagList.
Also, I keep on having this other issue as well. I keep this code in my Master page, and my AJAX returns 'success' on almost every page. I only (and always) get the error alert when I navigate to a page that actually contains something of id="ParentTags"
. I don't see why this is happening, because my $('#ParentTags').tagSuggest();
is definitely after my AJAX call.
I realize that this is probably just some dumb conventions error, but I am new to this and I'm here to learn from you guys. Thanks in advance!
$(function() {
var myTagList = ['test', 'testMore', 'testALot'];
$.ajax({
type: "POST",
url: 'Admin/GetTagList',
dataType: 'json',
success: function(resultTags) {
myTagList = resultTags;
alert(myTagList[0]);
setGlobalTags(myTagList);
},
error: function() {
alert('Error');
setGlobalTags(myTagList);
}
});
setGlobalTags(myTagList);
$('#ParentTags').tagSuggest();
});
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