How do I make a class whose interface matches double, but upon which templates can be specialized?
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by Neil G
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Published on 2010-06-17T02:40:51Z
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2010/06/17
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How do I make a class whose interface matches double, but whose templated types do not dynamic cast to double?
The reason is that I have a run-time type system, and I want to be able to have a type that works just like double:
template<int min_value, int max_value>
class BoundedDouble: public double {};
And then inherit use template specialization to get run-time information about that type:
template<typename T>
class Type { etc. }
template<int min_value, int max_value>
class Type<BoundedDouble<min_value, max_value>> { int min() const { return min_value; } etc. }
But, you can't inherit from double...
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