javascript error: variable is not defined

Posted by Hristo on Stack Overflow See other posts from Stack Overflow or by Hristo
Published on 2010-06-17T18:37:53Z Indexed on 2010/06/17 18:43 UTC
Read the original article Hit count: 213

Filed under:
|
|
to is not defined
[Break on this error] setTimeout('updateChat(from, to)', 1); 

I'm getting this error... I'm using Firebug to test and this comes up in the Console. The error corresponds to line 71 of chat.js and the whole function that wraps this line is:

function updateChat(from, to) {

    $.ajax({
        type: "POST",
        url: "process.php",
        data: {
            'function': 'getFromDB',
            'from': from,
            'to': to
        },
        dataType: "json",
        cache: false,
        success: function(data) {

            if (data.text != null) {
                for (var i = 0; i < data.text.length; i++) {  
                    $('#chat-box').append($("<p>"+ data.text[i] +"</p>"));
                }
                document.getElementById('chat-box').scrollTop = document.getElementById('chat-box').scrollHeight;
            }
            instanse = false;
            state = data.state;
            setTimeout('updateChat(from, to)', 1); // gives error
        },  
    });
}

This links to process.php with function call getFromDB and the code for that is:

case ('getFromDB'):

    // get the sender and receiver user IDs from their user names
    $from = mysql_real_escape_string($_POST['from']);
    $query  = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$from' LIMIT 1";
    $result = mysql_query($query) or die(mysql_error());
    $row = mysql_fetch_assoc($result);
    $fromID = $row['user_id'];  

    $to = mysql_real_escape_string($_POST['to']);
    $query  = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$to' LIMIT 1";
    $result = mysql_query($query) or die(mysql_error());
    $row = mysql_fetch_assoc($result);
    $toID = $row['user_id'];

    $query = "SELECT * FROM `Messages` WHERE `from_id` = '$fromID' AND `to_id` = '$toID' LIMIT 1";
    $result = mysql_query($query);
    while($row = mysql_fetch_assoc($result)) {

        $text[] = $line = $row['message'];
        $log['text'] = $text;

    }

    break;

So I'm confused with the line that is giving the error. setTimeout('updateChat(from,to)',1); aren't the parameters to updateChat the same parameters that came into the function? Or are they being pulled in from somewhere else and I have to define to and from else where? Any ideas how to fix this error?

Thanks, Hristo

© Stack Overflow or respective owner

Related posts about php

Related posts about JavaScript