php: showing my country based on my IP, mysql optimized

Posted by andufo on Stack Overflow See other posts from Stack Overflow or by andufo
Published on 2010-06-17T15:36:39Z Indexed on 2010/06/17 15:53 UTC
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I'm downloaded WIPmania's worldip table from http://www.wipmania.com/en/base/ -- the table has 3 fields and around 79k rows:

  • startip // example: 3363110912
  • endip // example: 3363112063
  • country // example: AR (Argentina)

So, lets suppose i'm in Argentina and my IP address is: 200.117.248.17

1) I use this function to convert my ip to long

function ip_address_to_number($ip) {
    if(!$ip) {
        return false;
    } else {
        $ip = split('\.',$ip);
        return($ip[0]*16777216 + $ip[1]*65536 + $ip[2]*256 + $ip[3]);
    }
}

2) I search for the proper country code by matching the long converted ip:

$sql = 'SELECT * FROM worldip WHERE '.ip_address_to_number($_SERVER['REMOTE_ADDR']).' BETWEEN startip AND endip';

which is equivalent to: SELECT country FROM worldip WHERE 3363174417 BETWEEN startip AND endip (benchmark: Showing rows 0 - 0 (1 total, Query took 0.2109 sec))

Now comes the real question.

What if another bunch of argentinian guys also open the website and they all have these ip addresses:

  • 200.117.248.17
  • 200.117.233.10
  • 200.117.241.88
  • 200.117.159.24

Since i'm caching all the sql queries; instead of matching EACH of the ip queries in the database, would it be better (and right) just to match the 2 first sections of the ip by modifying the function like this?

function ip_address_to_number($ip) {
    if(!$ip) {
        return false;
    } else {
        $ip = split('\.',$ip);
        return($ip[0]*16777216 + $ip[1]*65536);
    }
}

(notice that the 3rd and 4th splitted values of the IP have been removed).

That way instead of querying these 4 values:

  • 3363174417
  • 3363170570
  • 3363172696
  • 3363151640

...all i have to query is: 3363110912 (which is 200.117.0.0 converted to long).

Is this right? any other ideas to optimize this process? Thanks!

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