Python Numpy Structured Array (recarray) assigning values into slices
Posted
by user368877
on Stack Overflow
See other posts from Stack Overflow
or by user368877
Published on 2010-06-17T02:55:14Z
Indexed on
2010/06/17
3:03 UTC
Read the original article
Hit count: 307
Hi,
The following example shows what I want to do:
>>> test
rec.array([(0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0),
(0, 0, 0), (0, 0, 0), (0, 0, 0), (0, 0, 0)],
dtype=[('ifAction', '|i1'), ('ifDocu', '|i1'), ('ifComedy', '|i1')])
>>> test[['ifAction', 'ifDocu']][0]
(0, 0)
>>> test[['ifAction', 'ifDocu']][0] = (1,1)
>>> test[['ifAction', 'ifDocu']][0]
(0, 0)
So, I want to assign the values (1,1)
to test[['ifAction', 'ifDocu']][0]
. (Eventually, I want to do something like test[['ifAction', 'ifDocu']][0:10] = (1,1)
, assigning the same values for for 0:10
. I have tried many ways but never succeeded. Is there any way to do this?
Thank you, Joon
© Stack Overflow or respective owner