Sending HTML email from PHP
Posted
by KevinM
on Stack Overflow
See other posts from Stack Overflow
or by KevinM
Published on 2010-06-17T04:35:04Z
Indexed on
2010/06/17
4:43 UTC
Read the original article
Hit count: 287
I am trying to send a simple HTML e-mail from PHP. The code below simply results in a blank e-mail in GMail. It also has an empty attachment called 'noname', which is not at all what I want; though that might just be a symptom of it not working.
The code I am using is:
<?php
//define the receiver of the email
$to = '[email protected]';
//define the subject of the email
$subject = 'Test HTML email';
//create a boundary string. It must be unique
//so we use the MD5 algorithm to generate a random hash
$random_hash = md5(date('r', time()));
//define the headers we want passed. Note that they are separated with \r\n
$headers = "From: [email protected]\r\nReply-To: [email protected]";
//add boundary string and mime type specification
$headers .= "\r\nContent-Type: multipart/alternative; boundary=\"PHP-alt-".$random_hash."\"";
//define the body of the message.
ob_start(); //Turn on output buffering
?>
--PHP-alt-<?php echo $random_hash; ?>
MIME-Version: 1.0
Content-Type: text/plain; charset="iso-8859-1"
Content-Transfer-Encoding: 7bit
Hello World!!!
This is simple text email message.
--PHP-alt-<?php echo $random_hash; ?>
MIME-Version: 1.0
Content-Type: text/html; charset="iso-8859-1"
Content-Transfer-Encoding: 7bit
<h2>Hello World!</h2>
<p>This is something with <b>HTML</b>formatting.</p>
--PHP-alt-<?php echo $random_hash; ?>--
<?
//copy current buffer contents into $message variable and delete current output buffer
$message = ob_get_clean();
//send the email
$mail_sent = @mail( $to, $subject, $message, $headers );
//if the message is sent successfully print "Mail sent". Otherwise print "Mail failed"
echo $mail_sent ? "Mail sent" : "Mail failed";
© Stack Overflow or respective owner