Using xmlhttp.open() how do I add more than one parameter to url?

Posted by creocare on Stack Overflow See other posts from Stack Overflow or by creocare
Published on 2010-06-17T22:01:10Z Indexed on 2010/06/17 22:23 UTC
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AJAX

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variable

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get

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xmlhttp

I have this code.

xmlhttp.open("GET","getuser.php?q="+str,true);

where q="+str

I want to pass a second var how do I do this?

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