Extending the method pool of a concrete class which is derived by an interface
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by CelGene
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Published on 2010-06-18T16:39:15Z
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2010/06/18
16:43 UTC
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Hello, I had created an interface to abstract a part of the source for a later extension. But what if I want to extend the derived classes with some special methods? So I have the interface here:
class virtualFoo
{ public: virtual ~virtualFoo() { }
virtual void create() = 0;
virtual void initialize() = 0;
};
and one derived class with an extra method:
class concreteFoo : public virtualFoo
{ public: concreteFoo() { } ~concreteFoo() { }
virtual void create() { }
virtual void initialize() { }
void ownMethod() { }
};
So I try to create an Instance of concreteFoo and try to call ownMethod like this:
void main()
{ virtualFoo* ptr = new concreteFoo(); concreteFoo* ptr2 = dynamic_cast(ptr);
if(NULL != ptr2)
ptr2->ownMethod();
}
It works but is not really the elegant way. If I would try to use ptr->ownMethod(); directly the compiler complains that this method is not part of virtualFoo. Is there a chance to do this without using dynamic_cast?
Thanks in advance!
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