How to print value of a variable (which can be "-n" or "-e") in bash?

Posted by Vi on Stack Overflow See other posts from Stack Overflow or by Vi
Published on 2010-06-18T14:03:28Z Indexed on 2010/06/18 15:33 UTC
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bash

How to print "-n", "-e" or "-neeenen" from bash (without a newline at the end, without invoking of external programs)?

Q="-n"

echo -n "$Q" # fail

echo -- "$Q" # fail

cat <<< "$Q" # fail, also starts external program

printf -- '%s' "$Q" # success, ~~but starts external program~~

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How to print value of a variable (which can be "-n" or "-e") in bash? - Developer IT

How to print value of a variable (which can be "-n" or "-e") in bash?

bash

Related posts about bash

launching a program from bash causes bash to go to new prompt

How to debug a .bash_profile

Every command fails with "command not found" after changing .bash_profile?

Is there any fundamental difference between piping in mac and linux?

why is $0 set to -bash?

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