What is the difference between using $1 vs \1 in Perl regex substitutions?
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        Published on 2010-06-18T08:44:51Z
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I'm debugging some code and wondered if there is any practical difference between $1 and \1 in Perl regex substitutions
For example:
my $package_name = "Some::Package::ButNotThis";
$package_name =~ s{^(\w+::\w+)}{$1};  
print $package_name; # Some::Package
This following line seems functionally equivalent:
$package_name =~ s{^(\w+::w+)}{\1};
Are there subtle differences between these two statements? Do they behave differently in different versions of Perl?
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