Project Euler 1: (Iron)Python
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by Ben Griswold
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Published on Mon, 13 Sep 2010 00:05:11 +0000
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2010/12/06
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In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 1.
As always, any feedback is welcome.
# Euler 1 # http://projecteuler.net/index.php?section=problems&id=1 # If we list all the natural numbers below 10 that are # multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of # these multiples is 23. Find the sum of all the multiples # of 3 or 5 below 1000. import time start = time.time() print sum([x for x in range(1000) if x % 3== 0 or x % 5== 0]) print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue') # Also cool def constraint(x): return x % 3 == 0 or x % 5 == 0 print sum(filter(constraint, range(1000)))
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