Project Euler 9: (Iron)Python
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by Ben Griswold
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Published on Mon, 13 Sep 2010 02:48:51 +0000
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2010/12/06
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In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 9.
As always, any feedback is welcome.
# Euler 9 # http://projecteuler.net/index.php?section=problems&id=9 # A Pythagorean triplet is a set of three natural numbers, # a b c, for which, # a2 + b2 = c2 # For example, 32 + 42 = 9 + 16 = 25 = 52. # There exists exactly one Pythagorean triplet for which # a + b + c = 1000. Find the product abc. import time start = time.time() product = 0 def pythagorean_triplet(): for a in range(1,501): for b in xrange(a+1,501): c = 1000 - a - b if (a*a + b*b == c*c): return a*b*c print pythagorean_triplet() print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')
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