The internal storage of a DATETIME value

Posted by Peter Larsson on SQL Team See other posts from SQL Team or by Peter Larsson
Published on Fri, 05 Nov 2010 14:10:11 GMT Indexed on 2010/12/06 16:58 UTC
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SELECT  [Now],

        BinaryFormat,

        SUBSTRING(BinaryFormat, 1, 4) AS DayPart,

        SUBSTRING(BinaryFormat, 5, 4) AS TimePart,

        CAST(SUBSTRING(BinaryFormat, 1, 4) AS INT) AS [Days],

        DATEADD(DAY, CAST(SUBSTRING(BinaryFormat, 1, 4) AS INT), 0) AS [Today],

        CAST(SUBSTRING(BinaryFormat, 5, 4) AS INT) AS [Ticks],

        DATEADD(MILLISECOND, 1000.E / 300.E * CAST(SUBSTRING(BinaryFormat, 5, 4) AS INT), 0) AS Peso

FROM    (

            SELECT  GETDATE() AS [Now],

                    CAST(GETDATE() AS BINARY(8)) AS BinaryFormat

        ) AS d

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