Simple continuously running XMPP client in python
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Published on 2010-11-24T17:01:48Z
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2010/12/22
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I'm using python-xmpp to send jabber messages. Everything works fine except that every time I want to send messages (every 15 minutes) I need to reconnect to the jabber server, and in the meantime the sending client is offline and cannot receive messages.
So I want to write a really simple, indefinitely running xmpp client, that is online the whole time and can send (and receive) messages when required.
My trivial (non-working) approach:
import time
import xmpp
class Jabber(object):
def __init__(self):
server = 'example.com'
username = 'bot'
passwd = 'password'
self.client = xmpp.Client(server)
self.client.connect(server=(server, 5222))
self.client.auth(username, passwd, 'bot')
self.client.sendInitPresence()
self.sleep()
def sleep(self):
self.awake = False
delay = 1
while not self.awake:
time.sleep(delay)
def wake(self):
self.awake = True
def auth(self, jid):
self.client.getRoster().Authorize(jid)
self.sleep()
def send(self, jid, msg):
message = xmpp.Message(jid, msg)
message.setAttr('type', 'chat')
self.client.send(message)
self.sleep()
if __name__ == '__main__':
j = Jabber()
time.sleep(3)
j.wake()
j.send('[email protected]', 'hello world')
time.sleep(30)
The problem here seems to be that I cannot wake it up. My best guess is that I need some kind of concurrency. Is that true, and if so how would I best go about that?
EDIT: After looking into all the options concerning concurrency, I decided to go with twisted and wokkel. If I could, I would delete this post.
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