C++ STL type_traits question.
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Kim Sun-wu
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Published on 2010-12-30T07:48:18Z
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2010/12/30
7:54 UTC
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I was watching the latest C9 lecture and noticed something interesting..
In his introduction to type_traits, Stephan uses the following (as he says, contrived) example:
template <typename T>
void foo(T t, true_type)
{
std::cout << t << " is integral";
}
template <typename T>
void foo(T t, false_type)
{
std::cout << t << " is not integral";
}
template <typename T>
void bar(T t)
{
foo(t, typename is_integral<T>::type()
);
}
This seems to be far more complicated than:
template <typename T>
void foo(T t)
{
if(std::is_integral<T>::value
)
std::cout << "integral";
else
std::cout << "not integral";
}
Is there something wrong with the latter way of doing it? Is his way better? Why?
Thanks.
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