Given a database table where multiple rows have the same values and only the most recent record is to be returned
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by Jim Lahman
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Published on Mon, 03 Jan 2011 21:09:25 GMT
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2011/01/03
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I have a table where there are multiple records with the same value but varying creation dates. A sample of the database columns is shown here:
1: select lot_num, to_char(creation_dts,'DD-MON-YYYY HH24:MI:SS') as creation_date
2: from coil_setup
3: order by lot_num
LOT_NUM CREATION_DATE
------------------------------ --------------------
1435718.002 24-NOV-2010 11:45:54
1440026.002 17-NOV-2010 06:50:16
1440026.002 08-NOV-2010 23:28:24
1526564.002 01-DEC-2010 13:14:04
1526564.002 08-NOV-2010 22:39:01
1526564.002 01-NOV-2010 17:04:30
1605920.003 29-DEC-2010 10:01:24
1945352.003 14-DEC-2010 01:50:37
1945352.003 09-DEC-2010 04:44:22
1952718.002 25-OCT-2010 09:33:19
1953866.002 20-OCT-2010 18:38:31
1953866.002 18-OCT-2010 16:15:25
Notice that there are multiple instances of of the same lot number as shown in bold.
To only return the most recent instance, issue this SQL statement:
1: select lot_num, to_char(creation_date,'DD-MON-YYYY HH24:MI:SS') as creation_date
2: from
3: (4: select rownum r, lot_num, max(creation_dts) as creation_date
5: from coil_setup group by rownum, lot_num
6: order by lot_num
7: )8: where r < 100
LOT_NUM CREATION_DATE
------------------------------ --------------------
2019416.002 01-JUL-2010 00:01:24
2022336.003 06-OCT-2010 15:25:01
2067230.002 01-JUL-2010 00:36:48
2093114.003 02-JUL-2010 20:10:51
2093982.002 02-JUL-2010 14:46:11
2093984.002 02-JUL-2010 14:43:18
2094466.003 02-JUL-2010 20:04:48
2101074.003 11-JUL-2010 09:02:16
2103746.002 02-JUL-2010 15:07:48
2103758.003 11-JUL-2010 09:02:13
2104636.002 02-JUL-2010 15:11:25
2106688.003 02-JUL-2010 13:55:27
2106882.003 02-JUL-2010 13:48:47
2107258.002 02-JUL-2010 12:59:48
2109372.003 02-JUL-2010 20:49:12
2110182.003 02-JUL-2010 19:59:19
2110184.003 02-JUL-2010 20:01:03
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