Merging getComputedStyle and evaluate in Greasemonkey
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Keheliya Gallaba
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Published on 2011-01-03T03:25:19Z
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2011/01/03
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I need to get all the text nodes with a certain font-face in a page to an array. I tried..
textnodes = document.evaluate("//* [@style='font-family: foo;']//text()["
+ "not(ancestor::script) and not(ancestor::style)]", document,
null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null);
and
textnodes = document.evaluate("//* [@face='foo']//text()["
+ "not(ancestor::script) and not(ancestor::style)]", document,
null, XPathResult.UNORDERED_NODE_SNAPSHOT_TYPE, null);
But these does not work with pages that is styled by external CSS files. Seems getComputedStyle() is the way to go. I think what I need is something like..
var tags = document.getElementsByTagName('*');
for (var i in tags) {
var style = getComputedStyle(tags[i], '');
if (style.fontFamily.match(/foo/i)) {
textnodes.push(tags[i]);
}
}
But text nodes were not returned in this method. Is there anyway I can use a hybrid of xpath evaluate() and getComputedStyle() or any other way to achieve this?
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