How to get everything in the string, but a particular pattern
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José Leal
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Published on 2011-01-07T16:41:15Z
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2011/01/07
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Yet another regexp question:
I have a string as the following,
"This is a string, and I have a priority !1"
So I want to build a regexp that extracts my priority, which is this number 1 preceded by the "!". To extract it is very easy, "!([1-4])". But now I want to extract the text, leaving it out! How can I do that?
DETAIL: The !1 can be anywhere in the string, so this is also perfectly fine:
"This is a string, !1 and I have a priority"
Thanks!
UPDATE: I'm using scala
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