How to get everything in the string, but a particular pattern

Posted by José Leal on Stack Overflow See other posts from Stack Overflow or by José Leal
Published on 2011-01-07T16:41:15Z Indexed on 2011/01/07 16:54 UTC
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Yet another regexp question:

I have a string as the following,

"This is a string, and I have a priority !1"

So I want to build a regexp that extracts my priority, which is this number 1 preceded by the "!". To extract it is very easy, "!([1-4])". But now I want to extract the text, leaving it out! How can I do that?

DETAIL: The !1 can be anywhere in the string, so this is also perfectly fine:

"This is a string, !1 and I have a priority"

Thanks!

UPDATE: I'm using scala

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