Prepared statement help, Number of variables doesn't match number of parameters in prepared statement
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Sam Gabriel
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Published on 2011-01-08T08:37:14Z
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2011/01/08
8:54 UTC
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php
|prepared-statement
I'm getting this error : Number of variables doesn't match number of parameters in prepared statement every time I run this code:
$dbh = new mysqli("localhost", "***", "***", "pics");
$stmt = $dbh->prepare("INSERT INTO comments (username, picture, comment) VALUES (?, ?, ?)");
$stmt->bind_Param('s', $username);
$stmt->bind_Param('d', $picture);
$stmt->bind_Param('s', $comment);
$username=$_SESSION['username'];
$picture=$_GET['id'];
$comment=$_POST['comment'];
$stmt->execute();
What's the problem?
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